## § Euler tours

#### § Tucker's proof: undirected graph with all even degree has an euler tour

I find this proof much more intuitive because it's extremely clear where
the even condition is used.
- For each vertex $v$, arbitrarily pair edges incident at $v$ to getchains
`u --- v --- w`

. - Connect chains to get cycles.
- Find a spanning tree of cycles to get an euler tour, where we have anedge between two cycles if they share a common vertex.

It's super clear why we need all vertices to be even degree; You can't pair
up vertices otherwise!
#### § References